16cos^4(x)-16cos^2(x)+3=0

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Solution for 16cos^4(x)-16cos^2(x)+3=0 equation:


Simplifying
16cos4(x) + -16cos2(x) + 3 = 0

Multiply cos4 * x
16cos4x + -16cos2(x) + 3 = 0

Multiply cos2 * x
16cos4x + -16cos2x + 3 = 0

Reorder the terms:
3 + -16cos2x + 16cos4x = 0

Solving
3 + -16cos2x + 16cos4x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -16cos2x + -3 + 16cos4x = 0 + -3

Reorder the terms:
3 + -3 + -16cos2x + 16cos4x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -16cos2x + 16cos4x = 0 + -3
-16cos2x + 16cos4x = 0 + -3

Combine like terms: 0 + -3 = -3
-16cos2x + 16cos4x = -3

Reorder the terms:
3 + -16cos2x + 16cos4x = -3 + 3

Combine like terms: -3 + 3 = 0
3 + -16cos2x + 16cos4x = 0

The solution to this equation could not be determined.

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